In: Statistics and Probability
A manufacturer knows that their items have a normally distributed lifespan, with a mean of 12 years, and standard deviation of 0.5 years. If 5 items are picked at random, 4% of the time their mean life will be less than how many years? Give your answer to one decimal place.
solutio
Given that,
mean =
= 12
standard deviation =
= 0.5
n = 5
= 12
=
/
n = 0.5/
12=0.144
Using standard normal table,
P(Z < z) = 4%
= P(Z < z) = 0.04
z = -1.75 Using standard normal table,
Using z-score formula
= z *
+
= -1.75 *0.144+12
= 11.7