Question

JAVA

Write a number guessing game that will generate a random number between 1and 20 and ask the user to guess that number.

• The application should start by telling the user what the app does.
• You should then create the random number and prompt the user to guess it.
• You need to limit the number of times that the user can guess to 10 times.
• If the user guesses the number, display some message that tell them that they did it.
  • Else, tell the user to try again
• You should keep track of how many times they tried guessing and then display the number of times it took them to guess it if they did.
• If they exceed the number of allowed trials, display a message telling them that and display the number that you created.
• Display the remaining number of trials every time they guess.
• Tell the user if they are above or below the number.
• If they are close to guessing the number (about 2 numbers off) you should tell the user that they are very close to guessing the number.

Answer 1

Below is the Java code for mentioned problem statement:

import java.util.Random;
import java.util.Scanner;

public class Main
{ //program will start frome here main function
   public static void main(String[] args) {
   System.out.print("Application will generate a random number between 1-20. User has to Guess the number.\nSo lets Play the game!\n");
Scanner in = new Scanner(System.in);
// Generate random number between 1 to 20
int rand_num = new Random().nextInt(20) + 1;
int count, guess;
String choice;
while (true) {
count = 0;
while (true) {
System.out.print("Enter your guess : ");
// User input
guess = in.nextInt();
count++;
if(guess == rand_num) {
break;
} else if(guess < rand_num) {
System.out.println("Your guess was low, guess again");
} else {
System.out.println("Your guess was high, guess again");
}
}
System.out.println("It took you " + count + " guesses to guess correctly");
System.out.print("DO you want to try again(yes or no): ");
choice = in.next();
if(choice.equalsIgnoreCase("no")) {
break;
}
}
}
}