In: Statistics and Probability
The air temperature is measured every 6 hours for one week. The temperatures are given in the data table. Use the data to complete parts a through c below.
Data#   Temperature
1   42.3
2   59.8
3   41.3
4   48.6
5   42.5
6   56.8
7   49.9
8   47.7
9   53.5
10   58.7
11   53.4
12   42.8
13   58.3
14   58.4
15   59.6
16   40.4
17   57.2
18   56.9
19   52.9
20   40.4
21   41.4
22   51.1
23   51.4
24   48.3
25   43.3
26   59.8
27   51.4
28   47.2
a. Draw a systematic sample consisting of 2 temperatures, and then calculate the sampling error for the sample.
The sampling error for the sample is_____degrees°F.
b. Draw a systematic sample consisting of 4 temperatures, and then calculate the sampling error for the sample.
The sampling error for the sample is____degrees°F.
c. Draw a systematic sample consisting of 7 temperatures, and then calculate the sampling error for the sample.
The sampling error for the sample is____degrees°F.
in the systematic sampling, it selects from some starting point and then selects every kth element in population.
here for 2 samples, select data 1 and data 15
for sample 4 , select data 1 ,every 7th element(28/4=7)
for sample 7,select data 1,and then every 4th element(28/7=4)
| Sr. no | X | systematic sample consisting of 2 temperatures | systematic sample consisting of 4 temperatures | systematic sample consisting of 7 temperatures | 
| 1 | 42.3 | 42.3 | 42.3 | 42.3 | 
| 2 | 59.8 | |||
| 3 | 41.3 | |||
| 4 | 48.6 | |||
| 5 | 42.5 | 42.5 | ||
| 6 | 56.8 | |||
| 7 | 49.9 | |||
| 8 | 47.7 | 47.7 | ||
| 9 | 53.5 | 53.5 | ||
| 10 | 58.7 | |||
| 11 | 53.4 | |||
| 12 | 42.8 | |||
| 13 | 58.3 | 58.3 | ||
| 14 | 58.4 | |||
| 15 | 59.6 | 59.6 | 59.6 | |
| 16 | 40.4 | |||
| 17 | 57.2 | 57.2 | ||
| 18 | 56.9 | |||
| 19 | 52.9 | |||
| 20 | 40.4 | |||
| 21 | 41.4 | 41.4 | ||
| 22 | 51.1 | 51.1 | ||
| 23 | 51.4 | |||
| 24 | 48.3 | |||
| 25 | 43.3 | 43.3 | ||
| 26 | 59.8 | |||
| 27 | 51.4 | |||
| 28 | 47.2 | |||
| total | 1415.3 | 101.9 | 200.7 | 338.5 | 
population mean=ΣX/n =1415.3/28 = 50.5464
a)a. Draw a systematic sample consisting of 2 temperatures, and then calculate the sampling error for the sample.
sample mean for 2 samples = 101.9/2=50.95
sampling error = population mean-sample mean = 50.5464 - 50.95 = -0.4036
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b)
sample mean for 4 samples = 200.7/4=50.175
sampling error = 50.55 - 50.175 = 0.37
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c)
sample mean for 7 samples=338.5/7=48.3571
sampling error = 50.55-48.3571 = 2.189