In: Statistics and Probability
The air temperature is measured every 6 hours for one week. The temperatures are given in the data table. Use the data to complete parts a through c below.
Data# Temperature
1 42.8
2 55.6
3 41.3
4 44.6
5 43.4
6 58.5
7 46.1
8 45.6
9 41.6
10 59.9
11 51.1
12 46.3
13 54.6
14 56.2
15 54.9
16 43.2
17 51.7
18 51.8
19 49.8
20 47.4
21 46.2
22 55.2
23 51.9
24 41.3
25 50.2
26 59.8
27 49.3
28 48.4
a. Draw a systematic sample consisting of 2 temperatures, and then calculate the sampling error for the sample.
The sampling error for the sample is ___degreesF. (Round to two decimal places as needed.)
b. Draw a systematic sample consisting of 4 temperatures, and then calculate the sampling error for the sample.
The sampling error for the sample is ___degreesF. (Round to two decimal places as needed.)
c. Draw a systematic sample consisting of 7 temperatures, and then calculate the sampling error for the sample.
The sampling error for the sample is negative _____degreesF. (Round to two decimal places as needed.)
Column1 | Column2 | 2 | 4 | 7 |
1 | 42.8 | 42.8 | 42.8 | 42.8 |
2 | 55.6 | |||
3 | 41.3 | |||
4 | 44.6 | |||
5 | 43.4 | 43.4 | ||
6 | 58.5 | |||
7 | 46.1 | 46.1 | ||
8 | 45.6 | |||
9 | 41.6 | 41.6 | ||
10 | 59.9 | |||
11 | 51.1 | |||
12 | 46.3 | |||
13 | 54.6 | 54.6 | ||
14 | 56.2 | |||
15 | 54.9 | 54.9 | 54.9 | |
16 | 43.2 | |||
17 | 51.7 | 51.7 | ||
18 | 51.8 | |||
19 | 49.8 | |||
20 | 47.4 | |||
21 | 46.2 | 46.2 | ||
22 | 55.2 | 55.2 | ||
23 | 51.9 | |||
24 | 41.3 | |||
25 | 50.2 | 41.3 | ||
26 | 59.8 | |||
27 | 49.3 | |||
28 | 48.4 | |||
mean | 48.85 | 49.75 | 45.94286 |
a)
sampling error is difference between statistic and parameter
here sample mean and population mean
population mean =
49.5964286 |
sampling error for systematic sample consisting of 2 temperatures,
= 49.5964286 - 48.85
= 0.7464286
=0.75
b)
for 4
sampling error = |49.5964286 - 49.75|
= 0.15357
=0.15
c)
for 7
sampling error = |49.5964286 -45.94286|
= 3.65356