In: Statistics and Probability
Suppose the average number of donuts a nine-year old child eats in a month between 0.5 and 5 minutes, inclusive. Let X the average number of donuts a nineyear old child eats in a month. (Round probabilities to 4 decimal places) a. Then X ~ f(x) =
b. Find the probability that a randomly selected nine-year old child eats on average more than 2 donuts in month.
c. Find the 90th percentile for the average number of donuts a nine-year old child eats per month.
d. Find the probability that a different nine-year old child eats an average of more than two donuts given that his or her average is more than 1 donut per month.
(a)
Here X has uniform distribution between 0.5 and 5.
The pdf of X is
(b)
The probability that a randomly selected nine-year old child eats on average more than 2 donuts in month is
(c)
The 90th percentile, let P, for the average number of donuts a nine-year old child eats per month is,
(d)
and
Therefore,
The probability that a different nine-year old child eats an average of more than two donuts given that his or her average is more than 1 donut per month is,