Question

In: Chemistry

An analysis of the inorganic constituents of a raw water yielded the following results: Ca^+2= 63...

An analysis of the inorganic constituents of a raw water yielded the following results:
Ca^+2= 63 mg/L
Mg^+2= 15 mg/L
Na^+=20 mg/L
K^+= 10 mg/L
CO3^-2= 16 mg/L
HCO3^-1= 189 mg/L
SO4^-2= 80 mg/L
Cl^- =14 mg/L
a) Compute the total hardness
b) Find carbonate and non-carbonate hardness as mg/L CaCO3

Please show step by step solution. Thank you.

Solutions

Expert Solution


Related Solutions

A water sample was analyzed and was found to have the following constituents: Ca+2, mg/L 123...
A water sample was analyzed and was found to have the following constituents: Ca+2, mg/L 123 HCO3 - , mg/L 82 Mg+2, mg/L 12 SO4 -2, mg/L 122 Na+ , mg/L 22.1 Cl- , mg/L 112 K+ , mg/L 3.8 CO3 -2, mg/L 6.0 Fe+2, mg/L 5.8 Mn+2, mg/L 1.5 Temperature 25°C 1. Calculate each of the concentrations as mg/L as CaCO3. 2. Using the equilibrium expression for carbonate and bicarbonate, calculate the hydrogen ion concentration: a. as moles/L. b....
Identify three existing key customer constituents of Springfield Springs bottled water and perform a profitability analysis...
Identify three existing key customer constituents of Springfield Springs bottled water and perform a profitability analysis on each.
Ca(OH)2 dissolves exothermically in water and the molar solubility of Ca(OH)2 decreased as the temperature increases....
Ca(OH)2 dissolves exothermically in water and the molar solubility of Ca(OH)2 decreased as the temperature increases. What are the signs of Delta H and Delta S for dissolving Ca(OH)2?
A water analysis by a commerical analytical labortatory listed the following results of primary cations and...
A water analysis by a commerical analytical labortatory listed the following results of primary cations and anions in a submitted water sample. Cations - Ca2+ (93.8 mg/L) , Mg2+ (28.0 mg/L) , Na+ (13.7 mg/L) , K+ (30.2 mg/L) Anions - HCO- (164.7 mg/L) , SO4 2- (134.0 mg/L) , Cl- (92.5 mg/L) Do these results violate the principle of electroneutrality? Acceptable error - 0.1065 + (0.0155 x sum of anions) Provide a likely reason that H+ and OH- were...
When the ionic compound Ca(NO3)2 dissociates in water the equation is
When the ionic compound Ca(NO3)2 dissociates in water the equation is  $$ \begin{aligned} &\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2} \text { (s) } \rightarrow \mathrm{Ca}^{2+} \text { (aq) }+\mathrm{N}_{2} \text { (g) }+3 \mathrm{O}_{2} \text { (g) } \\ &\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2} \text { (s) } \rightarrow \mathrm{Ca}^{2+}(\mathrm{aq})+2 \mathrm{~N}^{3-}(\mathrm{aq})+6 \mathrm{O}^{2-}(\mathrm{aq}) \\ &\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{~s}) \rightarrow \mathrm{Ca}^{2+}(\mathrm{aq})+2 \mathrm{NO}_{3}^{-}(\mathrm{aq}) \\ &\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{~s}) \rightarrow \mathrm{Ca}^{2+}(\mathrm{aq})+\left(\mathrm{NO}_{3}\right)_{2}^{2-} \text { (aq) } \end{aligned} $$
Phosphate can be removed from drinking-water supplies by treating water with Ca(OH)2: Ca(OH)2(aq) + PO43-(aq) Ca5OH(PO4)3(s)...
Phosphate can be removed from drinking-water supplies by treating water with Ca(OH)2: Ca(OH)2(aq) + PO43-(aq) Ca5OH(PO4)3(s) + OH-(aq) How much Ca(OH)2 is required to remove 90% of the PO43- from 4.5 x 106 L of drinking water containing 25 mg/L of PO43-?
1. A model regressing consumption (C) on income (I) and wealth (W) yielded the following results....
1. A model regressing consumption (C) on income (I) and wealth (W) yielded the following results. All variables are measured in thousands of dollars. R2 = 0.86 R2 = 0.79 calc F = 17.42 n = 25 C = 402 + 0.83 I + 0.71 W (0.71) (6.21) (5.47) where the t-values are shown in parentheses. a. What is the meaning of the intercept term? b. Are the coefficients significant at the 5 percent level? c. Is the overall model...
What is the solubility of Ca(IO3)2 6H2O in (a) water; in (b) 0.150 M NaIO3; and...
What is the solubility of Ca(IO3)2 6H2O in (a) water; in (b) 0.150 M NaIO3; and in (c) 0.085 M Ca(NO3)2? For Ca(IO3)2 6H2O, Ksp = 2.03 x 10-6
A sample of solid Ca(OH)2 was stirred in water at a certain temperature until the solution...
A sample of solid Ca(OH)2 was stirred in water at a certain temperature until the solution contained as much dissolved Ca(OH)2 as it could hold. A 78.7-mL sample of this solution was withdrawn and titrated with 0.0696 M HBr. It required 68.0 mL of the acid solution for neutralization. (a) What was the molarity of the Ca(OH)2 solution? _________M (b) What is the solubility of Ca(OH)2 in water, at the experimental temperature, in grams of Ca(OH)2 per 100 mL of...
A sample of solid Ca(OH)2 was stirred in water at a certain temperature until the solution...
A sample of solid Ca(OH)2 was stirred in water at a certain temperature until the solution contained as much dissolved Ca(OH)2 as it could hold. A 59.6-mL sample of this solution was withdrawn and titrated with 0.0543 M HBr. It required 67.1mL of the acid solution for neutralization. (b) What is the solubility of Ca(OH)2 in water, at the experimental temperature, in grams of Ca(OH)2 per 100 mL of solution?   g/100mL
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT