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An analysis of the inorganic constituents of a raw water yielded the following results: Ca^+2= 63...

An analysis of the inorganic constituents of a raw water yielded the following results:
Ca^+2= 63 mg/L
Mg^+2= 15 mg/L
Na^+=20 mg/L
K^+= 10 mg/L
CO3^-2= 16 mg/L
HCO3^-1= 189 mg/L
SO4^-2= 80 mg/L
Cl^- =14 mg/L
a) Compute the total hardness
b) Find carbonate and non-carbonate hardness as mg/L CaCO3

Please show step by step solution. Thank you.

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Expert Solution

queen_honey_blossom answered 11 months ago
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