In: Statistics and Probability
A data set lists earthquake depths. The summary statistics are n=600, x=6.64 km, s=4.23 km. Use a 0.01 significance level to test the claim of a seismologist that these earthquakes are from a population with a mean equal to 6.00. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses?
Since n is very large, we use the z distribution.
Given:
= 6,
= 6.64, s = 4.23, n = 600,
= 0.01
The Hypothesis:
H0:
= 6 (Claim)
Ha:
6
The Test Statistic: The test statistic is given by the equation:
Z observed = 3.71
The p Value: The p value, 2 tailed for Z = 3.71, p value = 0.0002
This p value indicates the probability of getting a test statistic as extreme as or greater than that which has been obtained under the assumption/condition that the null hypothesis is true.
The Decision
Rule: If P value is <
, Then Reject H0.
The
Decision: Since P value (0.0002) is <
(0.01) , We Reject H0.
The Conclusion: There is sufficient evidence at the 99% significance level to warrant rejection of the claim that the earthquakes are from a population whose mean is equal to 6.