Question

3.04 g of Al react with 7.42g of I2. to form AlI3. How many grams of of AlI3are produced? which one is the limited reactant? Al +3Ia to Al2I3. Please show work

Answer 1

I.for the reaction   

the stoichiometric equation shows that 54gms of aluminium requires 762 gms of iodine so as to produce 816gms of

Limiting reagent is the substance which is consumed completly during the chemical change.

a) if 54 gms of aluminium requires 762gms of iodine to complete the reaction then 3.04 gms of Al requires

=

that means complete 7.42 gms of is utilised in the given proportions.hence iodine acts as limiting reagent.

and since limiting regent decides the amount of product formed

if 762gms of iodine participates it forms 816gms of

then 7.42 gms forms

and

II. for reaction

108gms Al requires 762gms of iodine to produce 870gms of

b) if 108gms of Al requires 762gms of iodine then 3.04 gms requires

but only 7.42 gms is taken so it is completly utilised hence iodine acts as limiting reagent

so

if 762 gms of iodine produces 870 gms of then 7.42gms produces