Which of the following atoms would you predict to have a fourth-ionization energy very much greater...

Which of the following atoms would you predict to have a fourth-ionization energy very much greater than the third?

Na

Mg

Al

Si

P

Expert Solution

A:- Element Atomic number Outer most electronic configuration

Na 11 3s1

Mg 12 3s2

Al 13 3s2 3p1

Si 14 3s2 3p2

P 15 3s2 3p3

First three ionnisation energy for the removal of three electrons from the Al metal atom to form Al^3+ ion, it has noble gas, Ne configuration (stable elctronic configuration). i.e. 1s2 2s2 2p6

Al -----------> Al^3+ + 3e

The fourth electron remove from the noble gas electronic configuration, so it required very much greater energy than the third.

Al^3+ electronic configuaration is equal [Ne] configuration

A:- Al

queen_honey_blossom answered 2 years ago

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Which of the following atoms would you predict to have a fourth-ionization energy very much greater...

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Expert Solution

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