In: Computer Science
Write a program in java processing.
Write a program that does the following: · Assume the canvas size of 500X500. · The program asks the user to enter a 3 digit number. · The program then checks the value of the first and last digit of the number. · If the first and last digits are even, it makes the background green and displays the three digit number at the mouse pointer. · If the two digits are odd, it makes the background red and displays the three digit number at the mouse pointer. · If the first digit is odd and the third is even, it makes the background blue and display the three digit number at the mouse pointer. · The number entered by the user is displayed at the mouse pointer at all times irrespective of the location of the mouse pointer.
import javax.swing.JOptionPane;
int number;
color c;
void setup(){
size(500,500);
//asking, reading number
number=Integer.parseInt(JOptionPane.showInputDialog("Enter a three digit number: "));
//assuming user will always enter a valid three digit number
//fetching first digit by integer division of number by 100
int first=number/100;
//fetching last digit by modulo division by 10
int last=number%10;
//if first and last digits are even, assigning green color to c
if(first%2==0 && last%2==0){
c=color(0,255,0);
}
//if first and last digits are odd, assigning red color to c
else if(first%2!=0 && last%2!=0){
c=color(255,0,0);
}
//if first digit is odd and last digits is even, assigning blue color to c
else if(first%2!=0 && last%2==0){
c=color(0,0,255);
}
//there is still one more case which is not mentioned in the question, that is
//if first digit is even and second is odd, since not specified any other, I'm
//using a default gray color
else{
c=color(200,200,200);
}
}
void draw(){
//using c as background color
background(c);
//using black fill color
fill(0);
//drawing number at mouse position
text(""+number,mouseX,mouseY);
}
/*OUTPUT (note: mouse pointers are not visible while taking screenshots)*/