Question

Write a program that does the following:  Assume the canvas size of 500X500.  The program asks the user to enter a 3 digit number.  The program then checks the value of the first and last digit of the number.  If the first and last digits are even, it makes the background green and displays the three digit number at the mouse pointer.  If the two digits are odd, it makes the background red and displays the three digit number at the mouse pointer.  If the first digit is odd and the third is even, it makes the background blue and display the three digit number at the mouse pointer.  The number entered by the user is displayed at the mouse pointer at all times irrespective of the location of the mouse pointer. Hint: import javax.swing.JOptionPane; JOptionPane.showInputDialog("")

help me solve this using pde processing java

Answer 1

Here is the completed code for this problem. Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. If not, PLEASE let me know before you rate, I’ll help you fix whatever issues. Thanks

import javax.swing.JOptionPane;

int number;
color c;

void setup(){
  size(500,500);
  //asking, reading number
  number=Integer.parseInt(JOptionPane.showInputDialog("Enter a three digit number: "));
  //assuming user will always enter a valid three digit number
  //fetching first digit by integer division of number by 100
  int first=number/100;
  //fetching last digit by modulo division by 10
  int last=number%10;
  
  //if first and last digits are even, assigning green color to c
  if(first%2==0 && last%2==0){
    c=color(0,255,0);
  }
  //if first and last digits are odd, assigning red color to c
  else if(first%2!=0 && last%2!=0){
    c=color(255,0,0);
  }
  //if first digit is odd and last digits is even, assigning blue color to c
  else if(first%2!=0 && last%2==0){
    c=color(0,0,255);
  }
  //there is still one more case which is not mentioned in the question, that is
  //if first digit is even and second is odd, since not specified any other, I'm 
  //using a default gray color
  else{
    c=color(200,200,200);
  }
}



void draw(){
  //using c as background color
  background(c);
  //using black fill color
  fill(0);
  //drawing number at mouse position
  text(""+number,mouseX,mouseY);
  
}

/*OUTPUT*/