Question

I need the Java Code and Flowchart for the following program:

Suppose you are given a 6-by-6 matrix filled with 0s and 1s. All rows and all columns have an
even number of 1s. Let the user flip one cell (i.e., flip from 1 to 0 or from 0 to 1) and write a
program to find which cell was flipped. Your program should prompt the user to enter a 6-by-6
array with 0s and 1s and find the first row r and first column c where the even number of the
1s property is violated (i.e., the number of 1s is not even). The flipped cell is at (r, c).

Here is a sample run:

Enter a 6-by-6 matrix row by row:
1 1 1 0 1 1
1 1 1 1 0 0
0 1 0 1 1 1
1 1 1 1 1 1
0 1 1 1 1 0
1 0 0 0 0 1
The flipped cell is at (0, 1)

Answer 1

import java.util.Scanner;    //importing scanner class
class matrix{
  
    public static void main(String...args){
        int i,j;                         //variables declaration ,this variables are used in loops
        int row=0;                       //declaring rownumber(which row has odd 1s)
        int col=0;                       //declaring colnumber(which column has odd 1s)
      
        Scanner input=new Scanner(System.in); //creating object of scanner class
        int[][] array=new int[6][6];          //declaring 2 dimentional array of size 6*6
      
    for(i=0;i<6;i++){System.out.println("enter "+i+"row");
      for(j=0;j<6;j++){
          array[i][j]=input.nextInt();}}       //this loop is for taking input values into 2-dimentional array
        
        
     System.out.println("matrix is");
      for(i=0;i<6;i++){            //outerloop for row_number
      for(j=0;j<6;j++){            //innerloop for col_number
          System.out.print(array[i][j]+" ");}   //printing 2-dimentional array with values
        System.out.println();}
      
      
        for(i=0;i<6;i++){     //outerloop for row_number
        int count=0;           //initializing count=0
        for(j=0;j<6;j++){     //innerloop for col_number
          if(array[i][j]==1){
              count++;}}       //increamenting count if the row has 1.
            
          if(count%2==1){      //if row has odd no.of 1's
            row=i;             //make row=i(problem occured at row_number i)
        break;}}                // break the loop
      
      
          for(i=0;i<6;i++){     //outerloop for col_number
          int count=0;           //initializing count=0
          for(j=0;j<6;j++){      //innerloop for row_number
          if(array[j][i]==1){
              count++;}}        //increamenting count if the col has 1.
          if(count%2==1){        //if col has odd no.of 1's
            col=i;               //make col=i(problem occured at col_number i)
        break;}}                    // break the loop
      
System.out.print("The flipped cell is at ("+row+","+col+")");       //printing cell position
      
      
    }}