Question

In: Statistics and Probability

In class we talked about the effects of cigarette smoking on birthweight. We defined a model...

In class we talked about the effects of cigarette smoking on birthweight. We defined a model E ( O | C = c ) = (β0)^1 + ((β1)^1 x c) where O is birthweight in ounces and C is cigarettes smoked per day. Suppose instead we used the model E(L|P =p)=(β0)^2 +((β1)^2 x p) where L is birthweight in pounds and P is packs of cigarettes smoked per day (there are 20 cigarettes in a pack). What is the relationship between (β0)^1 and (β0)^2 and between (β1)^1 and (β1)^2? Give a descriptive interpretation of both (β1)^1 and (β1)^2.

Solutions

Expert Solution

Solution

Back-up Theory

CHANGE OF SCALE

If a variable X is transformed by multiplying or dividing it by a constant, the transformation is called Change of Scale.

Effect of Change of Scale on various statistical measures

If U = bX and V = dY, ………………………………………………………………………. (1)

then

Ubar = bXbar, Vbar = dYbar ………………………………………………………………..(2)

Var (U) = σ2U = b2Var(X) = c2σ2X and Var (V) = σ2V = d2Var(Y) = d2σ2Y ………………….. (3)

Cov(U, V) = bdCov(X, Y) ……………………………………………………………………. (4)

Now to work out the solution,

Since a pound is 16 ounces and one pack = 20 cigarettes,

L = (1/16)o and P = 20c, here b = 20 and d = 1/16

Part (a)

β12 = Cov(P, L)/σ2P = (20/16)Cov(c, o)/400σ2c [vide (3) and (4)]

= (1/320){Cov(c, o)/σ2c} [vide (3) and (4)]

= (1/320)β1

Thus, the relationship between β12 and β1 is: β12 = β1/320 Answer 1

β 02 = Lbar - β12Pbar

= (1/16)obar – (β1/320)20cbar [vide (1) and Answer 1]

= (1/16)(obar – β1cbar)

= β 0/16.

Thus, the relationship between β02 and β0 is: β02 = β0/16 Answer 2

Part (b)

β12 represents the slope and its interpretation is that for every unit change in the number packs of cigarette smoked, the birth-weight would change by β12 pounds. If β12 is positive, an increase/decrease in the number packs of cigarette smoked will be accompanied by increase/decrease in the birth-weight. If β12 is negative, an increase/decrease in the number packs of cigarette smoked will be accompanied by decrease/increase in the birth-weight.

β02 represents the y-intercept and its interpretation is that even when no smoking is there, the birth-weight would be β02 pounds. Answer

DONE


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