In: Statistics and Probability
Given that,
possible chances (x)=1
sample size(n)=44
success rate ( p )= x/n = 0.023
success probability,( po )=0.5
failure probability,( qo) = 0.5
null, Ho:p=0.5
alternate, H1: p!=0.5
level of significance, alpha = 0.05
from standard normal table, two tailed z alpha/2 =1.96
since our test is two-tailed
reject Ho, if zo < -1.96 OR if zo > 1.96
we use test statistic z proportion = p-po/sqrt(poqo/n)
zo=0.02273-0.5/(sqrt(0.25)/44)
zo =-6.332
| zo | =6.332
critical value
the value of |z alpha| at los 0.05% is 1.96
we got |zo| =6.332 & | z alpha | =1.96
make decision
hence value of | zo | > | z alpha| and here we reject Ho
p-value: two tailed ( double the one tail ) - Ha : ( p != -6.33174
) = 0
hence value of p0.05 > 0,here we reject Ho
ANSWERS
---------------
null, Ho:p=0.5
alternate, H1: p!=0.5
test statistic: -6.332
critical value: -1.96 , 1.96
decision: reject Ho
p-value: 0
we have enough evidence to support the claim that whether giving
students directed reading activities would result in higher reading
performance