In: Statistics and Probability
Black | Hispanic | White | |
Pass | 9 | 6 | 41 |
Fail | 18 | 17 | 27 |
Use this data and a 0.05 significance level to test the claim that less than 58% of the minority candidates (Black and Hispanic candidates grouped together) pass the lieutenants exam.
Sample proportion, p-hat = A. 0.26
B. 0.17
C. 0.31
D. 0.62
Test Statistic, z = A. -3.27
B. -2.71
C. 1.12
D. 0.82
Critical z = A. -1.645
B. 1.645
C. -1.645, 1.645
D. -1.96, 1.96
P-Value = A. 0.001
B. 0.962
C. 0.051
D. 0.041
A. Reject the null hypothesis. There is sufficient evidence to show that less than 58% of minority candidates pass the lieutenants exam.
B. Reject the null hypothesis. There is insufficient evidence to show that less than 58% of minority candidates pass the lieutenants exam.
C. Fail to reject the null hypothesis. There is sufficient evidence to show that less than 58% of minority candidates pass the lieutenants exam.
D. Fail to reject the null hypothesis. There is insufficient evidence to show that less than 58% of minority candidates pass the lieutenants exam.
Following table shows the row total and column total:
Black | Hispanic | White | Total | |
Pass | 9 | 6 | 41 | 56 |
Fail | 18 | 17 | 27 | 62 |
Total | 27 | 23 | 68 | 118 |
Total number of black and Hispanic candidates is 27+23 = 50
Out of 50 minority candidates, 9+6 = 15 pass the exam so the sample proportion is
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Correct options (choosing best possible):
Sample proportion,
C. 0.31
Test Statistic, z = A. -3.27
Critical z = A. -1.645
P-Value = A. 0.001
A. Reject the null hypothesis. There is sufficient evidence to show that less than 58% of minority candidates pass the lieutenants exam.