Given a second order process: 2 AB → A 2 + B 2 with k = 0.0908
M-1min-1; and the initial concentration of AB = 0.941 M, calculate
the concentration of A2 after exactly 20 min. Enter the result with
3 sig. figs. exponential notation and no units.
for the unity feedback system, the open loop transfer functions
is
G(s)=K(s+2)(s+3) / (((s^2)+2*s+2)(s+4)(s+5)(s+6))
a. sketch the root locus (detail step wise)
b. find the jw-axis crossing and the gain. K, at the crossing
From 1+K*L(s)=0
L(s) = 1/((s+1)(s+2)(s+10))
Solve for gain K where the root locus passes through
the damping ratio. z=0.176. With out Matlab. Please show all
work.
Note: I know we need to use some trig and the
magnitude criteria but u cannot seem to figure it out. Thank
you!
Part A
Consider the second-order reaction:
2HI(g)→H2(g)+I2(g)
Rate law: k[H]^2
k= 6.4*10^-9 (mol*s) at 500 K
Initial rate = 1.6 * 10^-7 mol (l*s)
What will be the concentration of HI after t =
3.65×1010 s ([HI]t) for a reaction starting
under this condition?
Part B
In a study of the decomposition of the compound X via the
reaction
X(g)⇌Y(g)+Z(g)
the following concentration-time data were collected:
Time (min)
[X](M)
0
0.467
1
0.267
2
0.187
3
0.144
4
0.117
5...
Consider the unity feedback negative system with an open-loop
function G(s)= K (s^2+10s+24)/(s^2+3s+2).
a. Plot the locations of open-loop poles with X and zeros with O
on an s-plane.
b. Find the number of segments in the root locus diagram based
on the number of poles and zeros.
c. The breakaway point (the point at which the two real poles
meet and diverge to become complex conjugates) occurs when K =
0.02276. Show that the closed-loop system has repeated poles...
For the linear system x1+3x2=2
3x1+hx2=k
Find values for h and k such that the system has:
a) no solution
b) a unique solution
c) infinitely many solutions
1. Design 3rd order ideal low pass filter H(s).
Two poles are complex conjugates, and one pole is on the real axis.
2. transform H(s) to H(z). (Use impulse invariance
criterion)
1%criterion