Question

What volume of a 12.0 M KOH solution needs to be diluted to produce 475 mL of 3.10 M KOH solution?

Chemistry

Answer 1

In 3.10 M KOH solution

              3.10 moles of solute i.e KOH present in 1000 ml solution

              So, 475 ml of solution contain (3.10/1000) × 475

                     Number of moles of KOH i.e 1.4725 number of

                     Moles of KOH

In 12 M KOH solution

               12 moles of solute i.e KOH present in 1000 ml solution

Now, 1.4725 number of moles of KOH will present in

                                                  (1000/12) × 1.4725 ml solution

                                                 =122.7 ml solution

Hence, 122.7 ml of 12M KOH solution needs to be diluted to produce 475 ml of 3.10 KOH solution.