Titration of a 15.0 mL solution of KOH requires 17.0 mL of 0.0250 M H2SO4 solution....

Titration of a 15.0 mL solution of KOH requires 17.0 mL of 0.0250 M H2SO4 solution.

What is the molarity of the KOH solution?

M=?

Expert Solution

The reaction between sulphuric acid and potassium hydroxide is an example of neutralisation reaction between a base and an acid to give salt and water. The reaction is:

H₂SO₄ + KOH K₂SO₄ + H₂O

For any titration we know that:

M₁V₁ = M₂V_2,

Here, M₁ = molarity of KOH = ?, V₁ = volume of KOH = 15 mL,

M₂ = molarity of sulphuric acid = 0.0250, V₂ = volume of sulphuric acid = 17 mL.

by putting the values, we get the value of M₁ = 0.0283M.

Therefore, the molarity of KOH is 0.0283M

queen_honey_blossom answered 1 year ago

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