Question

The formation of tetrafluoroethylene from its elements is highly exothermic:

2F2(g) + 2C(s) ↔ F2C=CF2(g)

(a) If a mixture of F2, graphite, and C2F4 is at equilibrium in a closed container, will the reaction go to the right or to the left in F2 is added?

(b) Rare bacteria from the planet Teflon eats C2F4 and make Teflon for their cell walls. Will the reaction go to the right or to the left if these bacteria are added?

(c) Will the reaction go right or left if solid graphite is added? (Neglect any effect of increased pressure due to the decreased volume in the vessel when solid is added.)

(d) Will the reaction go right or left if the container is crushed to one-eight of its original volume?

(e) Does the equilibrium constant become larger or smaller if the container is heated?

Answer 1

Answer –

We know according the Le Chatelier's principle we know when we added the more amount of any species in any side then the reaction equilibrium will be shift to opposite side or if we remove the amount os species any side then equilibrium shift same side.

a) When we added F₂ in the mixture of F₂, graphite, and C₂F₄ and it is at equilibrium in a closed container the reaction will go to the right side means product side.

b) When bacteria are added in then there is equilibrium will be shifted towards left side means reactant side.

c) We know the in the equilibrium there is no solid phase counted, so the addition of solid graphite is no any change on the equilibrium, so reaction equilibrium will be unchanged.

d) When we crushed to one-eight of its original volume means we decrease the volume so the reaction equilibrium will shifted towards the less number of gases molecules and in this the moles of products side is less, so the reaction will go to the right side means product side.

e) We are given exothermic reaction means it release the heat and if we increase the temperature then there is reaction gets backward direction, so equilibrium will be shifted towards left side means reactant side.