Question
In: Chemistry
Increasing the volume will cause A (g) + 3B (s) <---> 2C (g) + energy The...
Increasing the volume will cause
A (g) + 3B (s) <---> 2C (g) + energy
|
The equilibrium to shift left/reverse reaction to be favoured. |
||
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The equilibrium to shift right/forward reaction to be favoured. |
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no effect on the equilibrium. |
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no effect on the equilibrium but will change the rate at which it is reached. |
Solutions
Expert Solution
The number of moles of gaseous reactants is 1. The number of
moles of gaseous products is 2.
The reaction proceeds with an increase in the number of moles of
gaseous species. When volume is increased, the pressure decreases.
The equilibrium will shift right. The forward reaction will be
favored. More and more reactants will be converted into products.
This will increase the pressure and will nullify the effect of
increase in the volume. This is in accordance with Le-Chatelier's
principle.
queen_honey_blossom answered 2 years agoRelated Solutions
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For the reaction
A(g) + 2B(g) → 2C(g) +
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the following data were collected at constant temperature.
Determine the correct rate law for this reaction.
Trial
Initial [A] (mol/L)
Initial [B] (mol/L)
Initial Rate (mol/(L·min)
1
0.125
0.200
7.25
2
0.375
0.200
21.75
3
0.250
0.400
14.50
4
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0.400
21.75
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Rate = k[A]2 [B]
Rate = k[A] [B]2
Rate = k[A]
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H2(g)+F2(g)→2HF(g)ΔH=−537kJ
C(s)+2F2(g)→CF4(g)ΔH=−680kJ
2C(s)+2H2(g)→C2H4(g)ΔH=+52.3kJ
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calculate ΔH for the reaction of ethylene with F2:
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.
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L
C. 52
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D. 3.61
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E. 22.4 L
What is the mass of CO2 in a 340. mL
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