Question

1. Write the complete electron configuration for the beryllium atom. ____


Using NOBLE GAS notation write the electron configuration for the nitrogen atom. ____

2.

The Pauli Exclusion Principle tells us that no two electrons in an atom can have the same four quantum numbers.

For each of the orbitals below list a set of possible quantum numbers.

(Give only one value for each.)

Orbital	n	l	ml	ms
1s	_____	______	______ _____		There are a total of ___ values possible for ml.
3p		____	____ ____ _____		There are a total of ___ values possible for ml.

3.

The Pauli Exclusion Principle tells us that no two electrons in an atom can have the same four quantum numbers.

For each of the orbitals below list a set of possible quantum numbers.

(Give only one value for each.)

Orbital	n	l	ml	ms
3s	____	_____	____	____	There are a total of _____ values possible for ml.
3d	____	_____	____	____	There are a total of _____ values possible for ml.

Answer 1

Answer –1) complete electron configuration for the beryllium atom -

We know, Be has atomic number 4, so

Electron configuration for the beryllium atom, Be = 1s² 2s²

Electron configuration for the nitrogen atom, N = [He] 2s² 2p³

2) We know there are four quantum number no two electrons in an atom can have the same four quantum numbers and this state by The Pauli Exclusion Principle.

Where, n is the principal quantum number and this is for principal electron shell, n = 1,2,3,..

l is the orbital angular momentum quantum number and it gives information about the the shape of an orbital. l = n-1 and l = 0,1,2,3,…

ml is the the magnetic quantum number and it tell us the number of orbitals and their orientation within a subshell. ml = -l to +l.

ms is the electron spin quantum number and it tell us direction of the electron spin

so, it is either + ½ or – ½ .

The following is the complete table for each given orbital

3)