Question

To understand and be able to use the rules for determining allowable orbital angular momentum states.

Several numbers are necessary to describe the states available to an electron in the hydrogen atom. The principal quantum number n determines the energy of the electron. The orbital quantum number l determines the total angular momentum of the electron, and the magnetic quantum number ml determines the component of the angular momentum parallel to a specific axis, usually the zaxis.

For a given principal quantum number n, the orbital quantum number can take integer values ranging from zero to n?1. For a given orbital quantum number l, the magnetic quantum number can take integer values from ?l to l. A fourth number, the spin ms, is important for interactions with magnetic fields and counting states. The spin can be either +1/2 or ?1/2, independent of the values of the other quantum numbers.

The energy of an electron in hydrogen is related to the principal quantum number by En=(?13.60eV)/n2. The orbital angular momentum is related to the orbital quantum number by L=?l(l+1)???????, and the orbital angular momentum in the z direction is related to the magnetic quantum number by Lz=ml?.

Part A

How many different values of l are possible for an electron with principal quantum number n = 2?

Express your answer as an integer.

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Part B

How many values of ml are possible for an electron with orbital quantum number l = 3?

Express your answer as an integer.

Part C

The quantum state of a particle can be specified by giving a complete set of quantum numbers (n, l, ml, ms). How many different quantum states are possible if the principal quantum number is n = 2?

To find the total number of allowed states, first write down the allowed orbital quantum numbers l, and then write down the number of allowed values of ml for each orbital quantum number. Sum these quantities, and then multiply by 2 to account for the two possible orientations of spin.

Express your answer as an integer.

Part D

Is the state n = 3, l = 3, ml = -2, ms =1/2 an allowable state? If not, why not?

A)	Yes it is an allowable state.
B)	No: The magnetic quantum number cannot be negative.
C)	No: The magnetic quantum number must equal the principal quantum number.
D)	No: The magnetic quantum number must equal the orbital quantum number.
E)	No: The orbital quantum number cannot equal the principal quantum number.

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Part E

What is the maximum angular momentum Lmax that an electron with principal quantum number n = 2 can have?

Express your answer in units of h. (You don't need to enter the , it is in the units field for you.)

Lmax =

_______________h

Answer 1