Part A The forensic technician at a crime scene has just prepared a luminol stock solution by adding 19.0 g of luminol into a total volume of 75.0 mL of H2O

Part A The forensic technician at a crime scene has just prepared a luminol stock solution by adding 19.0 g of luminol into a total volume of 75.0 mL of H2O . What is the molarity of the stock solution of luminol? Express your answer with the appropriate units. molarity of luminol solution = 1.43 M

Part B Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00×10?2 M . The diluted solution is then placed in a spray bottle for application on the desired surfaces. How many moles of luminol are present in 2.00 L of the diluted spray? Express your answer with the appropriate units. moles of luminol = 0.120 mol

Part C What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)? Express your answer with the appropriate units.

Expert Solution

Part A:

Number of moles = amount in g / molar mass

= 19.0 g/ 177 g/ mole

= 0.107 moles

Molarity = number of moles / volume in L

= 0.107 /0.075= 1.43 M

Part B

Molarity = number of moles / volume in L

6.00×10?2 M= number of moles / 2.0 L

number of moles= 0.12 Moles

part C:

Number of moles = 0.12 moles molarity = 1.43 M

Molarity = number of moles / volume inL

Volume in L= Number of moles / molarity

= 0.12/1.43

= 0.0839 L

= 83.9 ml

queen_honey_blossom answered 2 years ago

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