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A gas which obeys the equation of state, PV/RT=1 +BP ,
where B is a known
temperature-dependent parameter, is fed at a steady rate to an
insulated valve where its pressure is reduced from P1 to P2. Given
that the upstream temperature of the gas is T1 and that the
constant-pressure molar heat capacity of the gas in the ideal gas
state is given by Cp* = a + bT, where a and b are known constants,
derive an expression for the temperature T2 of the gas downstream
from the valve. Express your answer in terms of the parameters
given above. Neglect the effect of any kinetic energy change across
the valve.
(Chemical engineering)
This problem involves throttling of gas which obeys the equation of state
PV = RT(1+BP) ..............(1)
Let, subscript 1 represent the inlet condition and subscript 2 represent the outlet condition
Initial pressure and temperature are denoted by P1 and T1 respectively
Final pressure and temperature are denoted by P2 and T2 respectively
The molar heat capacity of the gas is given by the equation
Cp = a + bT ............(2)
Take energy balance across the valve
.............(3)
Let,
Q = Heat energy
W = work
K.E. = Kinetic energy
P.E. =Potential Energy
Ein = E1 = Q1 + W1 + K.E.1 + P.E.1
Eout = E2 = Q2 + W2 + K.E.2 + P.E.2
Substitue in eq.(3)
E = (Q1 + W1 + K.E.1 + P.E.1) - (Q2 + W2 + K.E.2 + P.E.2) ...........(4)
As the valve is insulated, there will be no Heat interaction
Hence Q1 = Q2 = 0
There is no change in elevation
Hence P.E.1 - P.E.2 = 0
Change in kinetic energy is negligible
Hence K.E.1 - K.E.2 = 0
rewriting Eq.(4)
E = W1 -W2
For a steady state process E = 0
Hence W1 -W2 = 0
Wtotal = 0
Consider the throttling process is carried out in two steps
1) Constant pressure expansion (i.e. at P1) to change temperature from T1 to T2
2) Constant temperature expansion (i.e. at T2) to reach pressure from P1 to P2
Work for constant pressure process is calculated as
W = PV
W1 = P1(V2 - V1) ................(5)
From eq.(1)
PV = RT(1+BP)
PV - BPRT = RT
P(V - BRT) = RT
P = RT / (V - BRT)
For constant pressure process, we can write
Rearranging above equation we get
V2RT1 = V1RT2
substitute in eq.(5)
......................(6)
Now, calculate work for constant temperature process
........................(7)
Adding eq.(6) and eq.(7)
..................................................Ans.