In: Math
There are 3 SPSS outputs in this homework assignment. The questions for each output are listed below. Please type your answers into this word document and submit it as an attachment in the assignment tab.
Q1. Researchers were interested in determining whether background music helped or hindered students’ performance on a math test. Students were randomly assigned to 1 of 3 groups: 1) no music; 2) music only; and 3) music with lyrics. Students were then given a math exam, scores which could range from 0 to 100.
N |
Mean |
Std. Deviation |
Std. Error |
95% Confidence Interval for Mean |
||
Lower Bound |
Upper Bound |
|||||
No music |
250 |
77.59 |
13.055 |
.826 |
75.96 |
79.21 |
Music only |
250 |
78.10 |
13.357 |
.845 |
76.44 |
79.77 |
Music and lyrics |
250 |
78.97 |
13.263 |
.839 |
77.32 |
80.62 |
Total |
750 |
78.22 |
13.221 |
.483 |
77.27 |
79.17 |
ANOVA |
|||||
minutes |
|||||
Sum of Squares |
df |
Mean Square |
F |
Sig. |
|
Between Groups |
244.595 |
2 |
122.297 |
.699 |
.497 |
Within Groups |
130668.664 |
747 |
174.925 |
||
Total |
130913.259 |
749 |
(a)
H0: Null Hypothesis: (Background music has no effect on students’ performance on a math test)
HA: Alternative Hypothesis: (At least one mean is different from the other 2 means) ( Background music helped or hindered students’ performance on a math test)
(b)
the total sample size = 750
(c)
Independent variable: Background music
Dependent variable: students’ performance on a math test
(d)
test statistic value = F = 0.699
(e)
F statistic = 0.699
Degrees of Freedom = 2, 747
By Technology, p - value = 0.4974
(f)
Since p - value = 0.4974 is greater than = 0.05, the difference is not significant. Fail to reject null hypothesis.
Conclusion:
The data do not support the claim that background music helped or
hindered students’ performance on a math test.
(g)
We do not need a post hoc analysis because the conclusion of ANOVA is that there is no significant difference between the 3 means.