Question

Currently the code outputs 3. Is there a way to make it output 32 writing logic in the parseint and not the main function?

#include <stdio.h>
#include <ctype.h>

int main()
{
printf("%d\n", parseint("32"));
return 0;
}

int parseint(char *str) {
int i=0;
while(str[i] != '\0'){
return (str[i] - '0');
i++;
}
return 1;   

Answer 1

The statement that is being updated is provided below:

return (str[i] - '0');

The above statement is updated as follows:

x = x*10 + str[i] - '0';

Explanation:

• Declare a variable x, that store the value of string that is being passed by the main function.
• And at last the value x is being returned to the main function which represents the whole string passed by the main function.

The complete correct code that display 32 is provided below:

Screenshot of the code:

//The modified lines are highlighted in yellow:

Sample Output:

Code To Copy:

#include <stdio.h>

#include <ctype.h>

int main()

{

printf("%d\n", parseint("32"));

return 0;

}

int parseint(char *str) {

int i=0 ,x = 0;

while(str[i] != '\0')

{

x = x*10 + str[i] - '0';

i++;

}

return x;  

}

//For any query please comment. Please provide the positive feedback. Thanks