Question
In: Civil Engineering
A beam extends over a span of 7.3 m and an overhang (cantilever) to the right...
A beam extends over a span of 7.3 m and an overhang (cantilever) to the right of the right support of 3 m (that is, the total length of the beam is 10.3 m.) The beam supports a service dead load of 18 t/m that does not include self-weight, and a service live load of 10 t/m. Assume the connection between the beam and the support is a simple pin or roller.
. If self-weight is 1.512 , the height(h) =90cm , width b=70 cm , dt= 83.5
Use fc' : 28 MPa, fy : 420 MPa
design the beam for shear including self weight
Solutions
Expert Solution
. I am really sorry for the
small disturbances in the calculation. I hope that you understand
the concept. If you understand the solution please like my solution
and support me. If you have any doubts please put a comment. Thank
you
Ally Wells answered 1 year agoRelated Solutions
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to a uniformly distributed load of
magnitude 8 kN/m for a distance of ‘0.6 L’ from the free end and
two concentrated loads one of
magnitude 15 kN at a distance ‘0.25 L’ m from the free end while
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1. A 3.5 m clear span singly reinforced cantilever beam has a rectangular section of b=300mm...
1. A 3.5 m clear span singly reinforced cantilever
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mm is reinforced with 2 bars of 32 mm diameter and 1 bar of 25mm
diameter in the tension zone. The
live load taken by the beam is 19 kN/m. Check if the beam is safe
to carry the above load . Use M25
and Fe500.
1. A 3.5 m clear span singly reinforced cantilever beam has a rectangular section of b=300mm...
1. A 3.5 m clear span singly reinforced cantilever
beam has a rectangular section of b=300mm and D=500
mm is reinforced with 2 bars of 32 mm diameter and 1 bar of 25mm
diameter in the tension zone. The
live load taken by the beam is 19 kN/m. Check if the beam is safe
to carry the above load . Use M25
and Fe500.
A cantilever beam 4m long carries a uniform load of 3.5 kN/m over a portion 1.5m...
A cantilever beam 4m long carries a uniform load of 3.5 kN/m
over a portion 1.5m from the free end. E = 200 GPa and I = 30 x
10^6 mm^4
Using Area Moment Method
a. Determine the rotation at the free end.
b. Determine the deflection at the free end
A simply supported beam of length 7m has a concentrated couple
Mo of 10kNm (Counterclockwise) applied at one end.
Using Double Integration Method
The maximum deflection is located at...
A cantilever beam 4m long carries a uniform load of 3.5 kN/m over a portion 1.5m...
A cantilever beam 4m long carries a uniform load of 3.5 kN/m
over a portion 1.5m from the free end. E = 200 GPa and I = 30 x
10^6 mm4
Using AMM (Area Moment Method):
Determine the rotation at the free end.
Determine the deflection at the free end.
(1) Select the lightest, rectangular Douglas fir section for the cantilever beam of15- ft span that...
(1) Select the lightest, rectangular Douglas fir section for the
cantilever beam of15- ft span that will carry a uniform load of 450
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A simply supported beam of 10m span carries a uniformly distributed load of 50kN/m spread over...
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distributed load of 50kN/m spread over 5m from the left support and
a 5kN concentrated load on its center . Its base is 250mm while
deep is 500mm. Calculate the maximum deflection in mm. E = 2.0x10^5
N/mm2. Use the area moment method
A cantilever beam AB is 4 m long and is fully restrained at the left support...
A cantilever beam AB is 4 m long and is fully restrained at the
left support A. The beam is loaded with a uniform load of 600 N/m
over a length of 2 m from the free end together with a clockwise
couple of magnitude 4800 N-m at the tip B. Determine the maximum
moment.
a. 3600 N-m
b. 8400 N-m
c. 1200 N-m
d. 5200 N-m
Use superposition to solve for applied stresses on a cantilever beam
Use superposition to solve for applied stresses on a cantilever
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