Question 5 - Half Lives:
Radioactive cesium (Cs-137) is one of many possible by-products
of a nuclear meltdown. The half-life for the decay of Cs-137 is
30.17 yr, what is the rate constant for its decay in
yr-1?
Enter the numerical answer in decimal format, do not include the
units.
For a first order reaction how many half-lives (t1/2)
must pass for the concentration of the reactant to reach 1/8 of its
original amount?
For a first order reaction having...
The half-life of cesium-137, released as a result of the
Fukushima Daiichi nuclear disaster, is 30.2 years. Determine the
number of years it would take for the amount of cesium-137 to
decrease to 7 % of the original amount released in the disaster.
Round your answer to the nearest number of years.
The half-life of 27Mg is 9.50 min. (a) Initially there were 4.80
× 1012 27Mg nuclei present. How many 27Mg nuclei are left 15.5 min
later?
× 10 nuclei Enter your answer in scientific notation.
b) Calculate the 27Mg activities (in Ci) at t = 0 and t = 15.5
min.
t = 0 Ci
t = 15.5 Ci
1) A first-order reaction has a half-life of 15.5 s . How long
does it take for the concentration of the reactant in the reaction
to fall to one-eighth of its initial value?
2) The rate constant for a certain reaction is k = 4.30×10−3 s−1
. If the initial reactant concentration was 0.350 M, what will the
concentration be after 8.00 minutes?
Half-life equation for first-order reactions:
t1/2=0.693k
where t1/2 is the half-life in seconds (s), and k
is the rate constant in inverse seconds (s−1).
A. What is the half-life of a first-order reaction with a rate
constant of 5.60×10−4
s−1?
B. What is the rate constant of a first-order reaction that
takes 150 seconds for the reactant concentration to drop to half of
its initial value?
C. A certain first-order reaction has a rate constant of
7.20×10−3 s−1. How long...