In: Chemistry
The half-life of 27Mg is 9.50 min. (a) Initially there were 4.80 × 1012 27Mg nuclei present. How many 27Mg nuclei are left 15.5 min later?
× 10 nuclei Enter your answer in scientific notation.
b) Calculate the 27Mg activities (in Ci) at t = 0 and t = 15.5 min.
t = 0 Ci
t = 15.5 Ci
Dear student,
Please give a positive ratings to this answer.
And stay safe....
With regards...