In: Statistics and Probability
a) If 1 of the men is randomly selected, find the probability his score is at least 590
b) If 16 of the men are randomly selected, find the probability that their mean score is at least 590
c) In part b why can the central limit theorem be used even though sample size does not exceed 30
d) If a random sample of 16 men does result in a mean score of 590 is there strong evidence to support the claim the course is effective? Why or why not?
Given,
= 509 , = 112
We convert this to standard normal as
P( X < x) = P( Z < x - / )
Therefore,
P( X >= 590) = P( Z >= 590 - 509 / 112)
= P( Z >= 0.7232)
= 0.2348
b)
Using central limit theorem,
P( < x) = P( Z < x - / / sqrt(n) )
P( >= 590) = P(Z >= 590 - 509 / 112 / sqrt(16) )
= P( Z > 2.8929)
= 0.0019
c)
Since original distribution is normally distributed, we can use central limit theorem in part b) even though
sample size not exceeding 30.
d)
Since probability for score 590 is unusual (below 0.05), we have strong evidence to support the
claim that the course is effective.