Question

Write the net ionic equation for the following reactions in solution.

A) Solutions of lithium chromate and barium chloride are mixed

B) Solutions of ammonium acetate and barium hydroxide are mixed

C) Solutions of Acetic acid and potassium hydrogen carbonate are mixed

Answer 1

Net ionic equation represents only those species, which are participating in the reaction. Spectator ions i.e. ions that exists in the same form on both reactants and products side are not included in net ionic equations.

Ans A)

Ionic equation for solution of lithium chromate and barium chloride can be written as follows:

2Li⁺(aq) + CrO₄^2-(aq) + Ba²⁺(aq) + 2Cl^-(aq) ------------> 2Li⁺(aq) + 2Cl^-(aq) + BaCrO₄(s)

Thus, net ionic equation excluding spectator ions can be written as follows:

CrO₄^2-(aq) + Ba²⁺(aq) ------------> BaCrO₄(s)

Ans B)

Ionic equation for solution of ammonium acetate and barium hydroxide can be written as follows:

2NH₄⁺(aq) + 2CH₃COO^-(aq) + Ba²⁺(aq) + 2OH^-(aq) --------------> 2NH₄⁺(aq) + 2OH^-(aq) + Ba(CH₃COO)₂(s)

Thus, net ionic equation excluding spectator ions can be written as follows:

2CH₃COO^-(aq) + Ba²⁺(aq) --------------> Ba(CH₃COO)₂(s)

Ans C)

Ionic equation for solution of acetic acid and potassium hydrogen carbonate can be written as follows:

CH₃COOH(aq) + K⁺(aq) + HCO₃^-(aq)   ----------> CH₃COO^-(aq) + K⁺(aq) + H₂O + CO₂(g)  

Thus, net ionic equation excluding spectator ion K+ can be written as follows:

CH₃COOH(aq) + HCO₃^-(aq)   ----------> CH₃COO^-(aq) + H₂O + CO₂(g)