Question

Please write the complete ionic equation and net ionic equation for the following chemical reactions.. 1) FeS + 2HCl = FeCl2 + H2S

2) H2S + Pb(NO3)3 = PbS + 2HNO3

3) 2Na+2H2O = 2NaOH + H2

4) Fe + CuSO4= FeSO4+ Cu

5) Cu + 2AgNO3 = 2 Ag+ Cu(NO3)2

6) Zn + 2HCl= ZnCl2 + H2

7) CuSO4 + 5H2O + H2O

8)H2SO4+2NaOH=Na2SO4+ 2H2O

9) Pb(NO3)2+Na2SO4= Pb2(SO4)+2NaNO3

10) N2O6Pb + HgN2S = 2NH4 (NO3)+PbS

11)CdN2O6+(NH4)2S= CdS + (2NH4)(NO3)

Answer 1

Key inputs:

1. Write the balanced molecular equation.
2. Write the state (s, l, g, aq) for each substance.
3. Split the strong electrolytes into ions to write the complete ionic equation (CIE).
4. Cross out (highlighted with bold letters in the below solution) the spectator ions that are present both the sides of the CIE.
5. Write the "leftovers" as the net ionic equation

Solution:

1). FeS + 2HCl FeCl₂ + H₂S:

1. FeS + 2HCl FeCl₂ + H₂S
2. FeS(s) + 2HCl(aq) FeCl₂(aq) + H₂S(g)
3. FeS(s) + 2H⁺(aq) + 2Cl^-(aq) Fe²⁺(aq) + 2Cl^-(aq) + H₂S(g)
4. FeS(s) + 2H⁺(aq) + 2Cl^-(aq) Fe²⁺(aq) + 2Cl^-(aq) + H₂S(g)
5. FeS(s) + 2H⁺(aq) Fe²⁺(aq) + H₂S(g)

2). H₂S + Pb(NO₃)₂ PbS + 2HNO₃

1. H₂S + Pb(NO₃)₂ PbS + 2HNO₃
2. H₂S(g) + Pb(NO₃)₂(aq) PbS(s) + 2HNO₃(aq)
3. H₂S(g) + Pb²⁺(aq) + 2NO₃^-(aq) PbS(s) + 2H⁺(aq) + 2NO₃^-(aq)
4. H₂S(g) + Pb²⁺(aq) + 2NO₃^-(aq) PbS(s) + 2H⁺(aq) + 2NO₃^-(aq)
5. H₂S(g) + Pb²⁺(aq) PbS(s) + 2H⁺(aq)

3). 2Na + 2H₂O 2NaOH + H₂:

1. 2Na + 2H₂O 2NaOH + H₂
2. 2Na(s) + 2H₂O(l) 2NaOH(aq) + H₂(g)
3. 2Na(s) + 2H₂O(l) 2Na⁺(aq) + 2OH^-(aq) + H₂(g)
4. Ther is no spectator ions.
5. 2Na(s) + 2H₂O(l) ​​​​​​​ 2Na⁺(aq) + 2OH^-(aq) + H₂(g)

4). Fe + CuSO₄ FeSO₄ + Cu:

1. Fe + CuSO₄ FeSO₄ + Cu
2. Fe(s) + CuSO₄(aq) FeSO₄(aq) + Cu(s)
3. Fe(s) + Cu²⁺(aq) + SO₄^2-(aq) Fe⁺(aq) + SO₄^2-(aq) + Cu(s)
4. Fe(s) + Cu²⁺(aq) + SO₄^2-(aq) Fe⁺(aq) + SO₄^2-(aq) + Cu(s)
5. Fe(s) + Cu²⁺(aq) Fe⁺(aq) + Cu(s)