In: Chemistry
If i have 1,000,000 gallons of water at a pH of 4.45 how many pounds of NaOH are need to raise this water to a pH of 7.8?
Please show work.
1,000,000 gallons of water = 3785411.78 L
at pH = 4.45 , [H3O+] = 10^-pH = 10^-4.45 = 3.55*10^-5 M
at pH = 7.8 , [H3O+] = 10^-pH = 10^-7.8 = 1.585*10^-8 M
the concentration of [H3O+] reduced = (3.55*10^-5)-(1.585*10^-8 ) = 3.548415*10^-5 M
concentration of [OH-] needed = 3.548415*10^-5 M
concentration of NaOH needed = 3.548415*10^-5 = W/mwt*1/V
3.548415*10^-5 = (w/40)*(1/3785411.78)
amount of NaOH needed = 5372.9 g
= 11.845 pound