The resistance of a starter for a 200-V, shunt motor is such that maximum starting current...

The resistance of a starter for a 200-V, shunt motor is such that maximum starting current is 30 A. When the current has decreased to 24 A, the starter arm is moved from the first to the second stud. Calculate the resistance between these two studs if the maximum current in the second stud is 34 A. The armature resistance of the motor is 0.4 Ω.

ANSWER [1.334 Ω]

Expert Solution

Manojponduru answered 1 year ago

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