The first part is easy, while the second part istedious.
PART A>>>> Q = I t
= (150 Coul/sec) ( 0.8sec) = 120 Coulombs. final
answer.
PART B>>> We first need to calculate thedrift
velocity of electrons in a Cu wire.
You will need to look and use the density of Cu = 8.95 g
/cm3
and the atomic mass
of Cu = 63.5 g/ mole.
The volume of 1 mole of Cu is 63.5g/mole /
8.95 g/cm3 =
7.09 cm3
/ mole.
Assuming that there is 1 free electron in each Cu atom,
the density of electrons in Cu is n= (6.02E23
electrons) / 7.09 cm3 =
8.48E22 e/cm3
converting this electron density to units ofelectrons/m3
, we get 8.48E28.
Now, the drift velocity v = I / ( n q A) ,where we know I, n, and q
, but need to find the crosssectional area A of the given
wire.
A = ? (0.005 m)2
/ 4 = 1.96E-5 m2
Thus, drift v = (150) / [(8.48E28)
(1.60E-19) (1.96E-5)] = 5.64E-4 m/s
PLEASE CHECK AND VERIFY ALL OF MY CALCULATOR WORK

Distance traveled by electrons = v t =
(5.64E-4 m/s) (0.8 sec) = 4.51E-4 m or 0.45 mm.