Consider the following reaction: HC2H3O2(aq)+H2O(l)?H3O+(aq)+C2H3O?2(aq) Kc=1.8

Consider the following reaction:
HC2H3O2(aq)+H2O(l)?H3O+(aq)+C2H3O?2(aq)
Kc=1.8

Expert Solution

               HC2H3O2(aq) + H2O(l) ------ H3O+(aq)   + C2H3O?2(aq)
Initial---         0.23 M                     0                             0
Change        - x                              x                             x
Final         0.23 - x                              x                             x

Note: K = [H3O+][C2H3O?2]/[HC2H3O2]

Therefore,

K = (x)^2/(0.23 -x) = 1.8x10^-5

as we can see Kc is very small therefore x also must be very small , therefore we can neglect x in (0.23-x)^2

so we get

x^2/(0.23) = 1.8x10^-5

or x = 2.03x10^-3 = 0.002303 M

as we know [H3O+] = x = 0.002303 M....... answer

queen_honey_blossom answered 4 months ago

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