Solve the initial value problem dy/dx = −(2x cos(x^2))y +
6(x^2)e^(− sin(x^2)) , y(0) = −5
Solve the initial value problem dy/dt = (6t^5/(1 + t^6))y + 7(1
+ t^6)^2 , y(1) = 8.
Find the general solution of dy/dt = (2/t)*y + 3t^2* cos3t
A. Find the region bounded by the curves y = (x−3)^2 and y =
12−4x. Show all of your work.
B. Find the equation of the tangent line to the curve 5x^2 −6xy
+ 5y^2 = 4 at the point (1,1) Show all of your work. Thanks