Question

Write balanced complete ionic and net ionic equations for each of the following reactions.

Part A

HI(aq)+KOH(aq)→H2O(l)+KI(aq)

Express your answer as a complete ionic equation. Identify all of the phases in your answer.

Part B

Express your answer as a net ionic equation. Identify all of the phases in your answer.

Part C

Na2SO4(aq)+CaI2(aq)→CaSO4(s)+2NaI(aq)

Express your answer as a complete ionic equation. Identify all of the phases in your answer.

Part D

Express your answer as a net ionic equation. Identify all of the phases in your answer.

Part E

2HClO4(aq)+Na2CO3(aq)→H2O(l)+CO2(g)+2NaClO4(aq)

Express your answer as a complete ionic equation. Identify all of the phases in your answer.

Part F

Express your answer as a net ionic equation. Identify all of the phases in your answer.

Part G

NH4Cl(aq)+NaOH(aq)→H2O(l)+NH3(g)+NaCl(aq)

Express your answer as a complete ionic equation. Identify all of the phases in your answer.

Part H

Express your answer as a net ionic equation. Identify all of the phases in your answer.

Answer 1

A)

we have below given equation

HI (aq) + KOH (aq) --> H2O (l) + KI (aq)

Total ionic equation is

Spectator ions should not be removed here. Spectator ions are part of total ionic equation

H+ (aq) + I- (aq) + K+ (aq) + OH- (aq) --> H2O (l) + K+ (aq) + I- (aq)

H+ (aq) + I- (aq) + K+ (aq) + OH- (aq) --> H2O (l) + K+ (aq) + I- (aq)

B)

Spectator ions should be removed now. Spectator ions are not part of total ionic equation

After removing Spectator ions, net ionic equation is:

H+ (aq) + OH- (aq) —> H2O (l)

Answer: H+ (aq) + OH- (aq) —> H2O (l)

C)

we have below given equation

Na2SO4 (aq) + CaI2 (aq) --> CaSO4 (s) + 2 NaI (aq)

Total ionic equation is

Spectator ions should not be removed here. Spectator ions are part of total ionic equation

2 Na+ (aq) + SO42- (aq) + Ca2+ (aq) + 2 I- (aq) --> CaSO4 (s) + 2 Na+ (aq) + 2 I- (aq)

2 Na+ (aq) + SO42- (aq) + Ca2+ (aq) + 2 I- (aq) --> CaSO4 (s) + 2 Na+ (aq) + 2 I- (aq)

D)

Spectator ions should be removed now. Spectator ions are not part of total ionic equation

After removing Spectator ions, net ionic equation is:

Ca2+ (aq) + SO42- (aq) --> CaSO4 (s)

Ca2+ (aq) + SO42- (aq) --> CaSO4 (s)

Only 4 parts at a time