Question

In: Statistics and Probability

Engineer wants to develop a model to describe the gas mileage of a sport utility vehicle....

  1. Engineer wants to develop a model to describe the gas mileage of a sport utility vehicle. He collects the data presented in following table.

2008 Model

Engine Size (liters)

Cylinders

Final Drive Ratio

Miles per Gallon

Mercedes Benz

5

8

4.38

13

Jeep Wrangler

3.8

6

3.21

16

Mitsubishi Endeavor

3.8

6

4.01

18

Toyota Land Cruiser

5.7

8

3.91

15

Kia Sorento

3.3

6

3.33

18

Jeep Commander Sport

4.7

8

3.73

15

Dodge Durango

4.7

8

3.55

15

Lincoln Navigator

5.4

8

3.73

15

Chevrolet Tahoe

4.8

8

3.23

16

Ford Escape

3

6

2.93

20

Ford Expedition

5.4

8

3.31

14

Buick Enclave

3.6

6

3.16

19

Cadillac Escalade

6.2

8

3.42

14

Hummer

3.7

5

4.56

15

Saab 9-7X

4.2

6

3.73

16

  1. Identify the dependent variable and independent variables.

  1. Build a multiple linear regression model to predict miles per gallon.

  1. Can this model used to make predictions? Explain.

Solutions

Expert Solution

  1. Identify the dependent variable and independent variables.

The dependent variable for this regression model is given as miles per gallon, while the independent variables for this regression model are given as engine size in liters, number of cylinders, and final drive ratio.

  1. Build a multiple linear regression model to predict miles per gallon.

A required multiple regression model by using excel to predict the miles per gallon is given as below:

Regression Statistics

Multiple R

0.882349692

R Square

0.778540978

Adjusted R Square

0.718143063

Standard Error

1.051642968

Observations

15

ANOVA

df

SS

MS

F

Significance F

Regression

3

42.76785108

14.25595036

12.89019627

0.000637609

Residual

11

12.16548225

1.105952932

Total

14

54.93333333

Coefficients

Standard Error

t Stat

P-value

Lower 95%

Upper 95%

Intercept

29.58398137

3.141907801

9.415929188

1.34438E-06

22.66868893

36.49927381

Engine Size (liters)

-1.275237681

0.615848639

-2.070699846

0.062697156

-2.630711395

0.080236032

Cylinders

-0.226707152

0.506257962

-0.447809555

0.66298163

-1.340973413

0.887559108

Final Drive Ratio

-1.755526363

0.666953946

-2.6321553

0.023317377

-3.223482098

-0.287570627

Required regression model or equation is given as below:

Miles per gallon = 29.58398137 - 1.275237681* Engine Size - 0.226707152* Cylinders - 1.755526363* Final Drive Ratio

  1. Can this model used to make predictions? Explain.

Yes, this model can used to make predictions because the p-value for this regression model is given as 0.0006376 which is very smaller than 1% level of significance. Also, multiple correlation coefficient is given as 0.8823 which suggest the strong linear relationship between the dependent variable and combination of independent variables.


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