In: Statistics and Probability
To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time (in minutes) needed to mix the material.
|
Manufacturer |
||||
| 1 | 2 | 3 | ||
| 18 | 28 | 21 | ||
| 24 | 26 | 20 | ||
| 22 | 31 | 24 | ||
| 20 | 27 | 23 | ||
a. Use these data to test whether the
population mean times for mixing a batch of material differ for the
three manufacturers. Use a=.05.
Compute the values below (to 2 decimals, if necessary).
| Sum of Squares, Treatment | |
| Sum of Squares, Error | |
| Mean Squares, Treatment | |
| Mean Squares, Error |
Calculate the value of the test statistic (to 2 decimals).
The -value is - Select your answer -less than .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 6
What is your conclusion?
- Select your answer -Conclude the mean time needed to mix a batch of material is not the same for all manufacturersDo not reject the assumption that mean time needed to mix a batch of material is the same for all manufacturersItem 7
b. At the .05 level of significance, use Fisher's LSD procedure to test for the equality of the means for manufacturers 1 and 3.
Calculate Fisher's LSD Value (to 2 decimals).
What is your conclusion about the mean time for manufacturer 1 and the mean time for manufacturer 3?

a)
| sum of square; treatment= | 114.67 |
| sum of square; error= | 44.00 |
| mean square; treatment= | 57.33 |
| mean square; error= | 4.89 |
value of the test statistic =11.73
p value is less than .01
Conclude the mean time needed to mix a batch of material is not the same for all manufacturers
Fisher's LSD Value =3.54
conclusion about the mean time for manufacturer 1 and the mean time for manufacturer 3 : not signifiicanlty different