In: Statistics and Probability
To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time (in minutes) needed to mix the material.
Manufacturer |
||||
1 | 2 | 3 | ||
18 | 28 | 21 | ||
24 | 26 | 20 | ||
22 | 31 | 24 | ||
20 | 27 | 23 |
a. Use these data to test whether the
population mean times for mixing a batch of material differ for the
three manufacturers. Use a=.05.
Compute the values below (to 2 decimals, if necessary).
Sum of Squares, Treatment | |
Sum of Squares, Error | |
Mean Squares, Treatment | |
Mean Squares, Error |
Calculate the value of the test statistic (to 2 decimals).
The -value is - Select your answer -less than .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 6
What is your conclusion?
- Select your answer -Conclude the mean time needed to mix a batch of material is not the same for all manufacturersDo not reject the assumption that mean time needed to mix a batch of material is the same for all manufacturersItem 7
b. At the .05 level of significance, use Fisher's LSD procedure to test for the equality of the means for manufacturers 1 and 3.
Calculate Fisher's LSD Value (to 2 decimals).
What is your conclusion about the mean time for manufacturer 1 and the mean time for manufacturer 3?
a)
sum of square; treatment= | 114.67 |
sum of square; error= | 44.00 |
mean square; treatment= | 57.33 |
mean square; error= | 4.89 |
value of the test statistic =11.73
p value is less than .01
Conclude the mean time needed to mix a batch of material is not the same for all manufacturers
Fisher's LSD Value =3.54
conclusion about the mean time for manufacturer 1 and the mean time for manufacturer 3 : not signifiicanlty different