In: Statistics and Probability
To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time (in minutes) needed to mix the material.
a. Use these data to test whether the
population mean times for mixing a batch of material differ for the
three manufacturers. Use a=.05
Compute the values below (to 2 decimals, if necessary).
Sum of Squares, Treatment | |
Sum of Squares, Error | |
Mean Squares, Treatment | |
Mean Squares, Error |
Calculate the value of the test statistic (to 2 decimals).
. At the a= .05 level of significance, use Fisher's LSD procedure to test for the equality of the means for manufacturers 1 and 3
Calculate Fisher's LSD Value (to 2 decimals).
1 | 2 | 3 | ||
15 | 35 | 17 | ||
21 | 33 | 16 | ||
19 | 38 | 20 | ||
17 | 34 | 19 |
Group 1 | Group 2 | Group 3 | Total | |
Sum | 72 | 140 | 72 | 284 |
Count, n | 4 | 4 | 4 | 12 |
Average, sum/n | 18 | 35 | 18 | |
Sum of square, Ʃ(xᵢ-x̅)² | 20 | 14 | 10 |
Number of treatment, k = 3
Total sample Size, N = 12
df(treatment) = k-1 = 2
df(error) = N-k = 9
df(total) = N-1 = 11
SS(treatment) = (Sum1)²/n1 + (Sum2)²/n2 + (Sum3)²/n3 - (Grand
Sum)²/ N = 770.6667
SS(error) = SS1 + SS2 + SS3 = 44
SS(total) = SS(treatment) + SS(error) = 814.6667
MS(treatment) = SS(treatment)/df(treatment)
= 385.3333
MS(error) = SS(error)/df(error) = 4.8889
Test statistic:
F = MS(treatment)/MS(error) =
78.82
p-value = F.DIST.RT(78.82, 2, 9) = 0.0000
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b) Critical t value at df = N-k = 9, tc = T.INV.2T(0.05, 9) = 2.262
LSD = t* √(2*MS(error)/n) = 2.262 *√(2*4.8889/4) = 3.54