Question

In: Physics

1. An ideal transformer has a primary with 25 turns and secondary with 15 turns. The...

1. An ideal transformer has a primary with 25 turns and secondary with 15 turns. The load resistor is 24 ? and the source voltage is 85 Vrms.What is the rms electric potential across the 24 ? load resistor?

Answer in units of Vrms

2. A transformer consists of two coils of wire wound on a common toroidal iron core. The mutual inductance of the pair is 483 mH and the current in the first coil decreases from 29 A to 0 in 2.9 s.

What is the induced emf in the second coil? Answer in units of V.

3.If the outer coil has 14.7 turns, a radius of 19 cm and length of 7.47 cm and the inner coil has 628 turns, a radius of 7 cm, and a length of 33.3 cm, find the mutual inductance of the circular coil and solenoid.

Answer in units of ?H

4. Now the current in the solenoid is increased linearly at a rate of di/dt = a =20.2 A/s.

What is the magnitude of the voltage E across the circular coil?

Answer in units of ?V.

Solutions

Expert Solution

1. An ideal transformer has a primary with 25 turns and secondary with 15 turns. The load resistor is 24 ? and the source voltage is 85 Vrms.What is the rms electric potential across the 24 ? load resistor?

V1/V2 = N1 / N2

so V2 = 85*15/25 = 51

so voltage across 24 ohms = 51 V rms

Answer in units of Vrms

2. A transformer consists of two coils of wire wound on a common toroidal iron core. The mutual inductance of the pair is 483 mH and the current in the first coil decreases from 29 A to 0 in 2.9 s.

What is the induced emf in the second coil?

V = M* di / dt = 483*0.001 8 ( 29-0) / 2.9 = 4.83 volts

Answer in units of V.

3.If the outer coil has 14.7 turns, a radius of 19 cm and length of 7.47 cm and the inner coil has 628 turns, a radius of 7 cm, and a length of 33.3 cm, find the mutual inductance of the circular coil and solenoid.

The mutual inductance = Uo*A1*ns*Nc = (note convert ns to turns per meter)

Uo*pi*0.07^2*628*100/33.3 *14.7 = 536.276579724 micro henry

Answer in units of ?H

4. Now the current in the solenoid is increased linearly at a rate of di/dt = a =20.2 A/s.

What is the magnitude of the voltage E across the circular coil?

E = M* di/dt = 536.276579724 * 0.000001 * 20.2 = 10832.7869104248 micro volts

Answer in units of ?V.


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