Question

An ideal transformer has 50 turns in its primary (input) and 450 turns in its secondary (output). 10.0-V ac is connected to the primary (input). a) What is the voltage on the secondary (output)? b) What is the secondary (output) current if a 10.0- resistor is connected to the secondary (output)? c) What is the power supplied to the primary (input)?

Answer 1

a)

The transformer follows -

Where N_s is the number of turns of secondary coil

            N_p is the number of turns of primary coil

            V_s is the secondary voltage

and    V_p is the primary voltage.

We are given - N_p = 50, N_s = 450, V_p = 10 . So, solving for V_s we get -

Hence, voltage on the secondary (output) is = 90 V.

-------------------------------------------------------------------------

b)

According to Ohm's law -

V = IR

So, for a 10 resistor the current in secondary circuit is -

Hence, the secondary(output) current = 9 A.

---------------------------------------------------------------------------

c)

In ideal transformer, the power input is same as the power output.

And the power output = VI = (90) x (9) W

                                   = 810 W.

_______________________________________