Question

In: Physics

An ideal transformer has 50 turns in its primary (input) and 450 turns in its secondary...

An ideal transformer has 50 turns in its primary (input) and 450 turns in its secondary (output). 10.0-V ac is connected to the primary (input). a) What is the voltage on the secondary (output)? b) What is the secondary (output) current if a 10.0- resistor is connected to the secondary (output)? c) What is the power supplied to the primary (input)?

Expert Solution

a)

The transformer follows -

Where N_s is the number of turns of secondary coil

N_p is the number of turns of primary coil

V_s is the secondary voltage

and V_p is the primary voltage.

We are given - N_p = 50, N_s = 450, V_p = 10 . So, solving for V_s we get -

Hence, voltage on the secondary (output) is = 90 V.

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b)

According to Ohm's law -

V = IR

So, for a 10 resistor the current in secondary circuit is -

Hence, the secondary(output) current = 9 A.

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c)

In ideal transformer, the power input is same as the power output.

And the power output = VI = (90) x (9) W

= 810 W.

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genius_generous answered 4 months ago

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