A neutron star has a mass of 3.35 × 1030 kg (about the mass of our...

A neutron star has a mass of 3.35 × 1030 kg (about the mass of our sun) and a radius of 6.09 × 103 m. Suppose an object falls from rest near the surface of such a star. How fast would it be moving after it had fallen a distance of 0.013 m? (Assume that the gravitational force is constant over the distance of the fall, and that the star is not rotating.)

Solutions

Expert Solution

Mass M = 3.35 × 10³⁰ kg

Radius R = 6.09 × 10³ m

Distance travel S = 0.013 m

Accleration due to gravity on star g = GM/R ²

Where G = Gravitational constant = 6.67 x10 ^-11 Nm ²/ kg ²

Substitute values you get g = ( 6.67 x10 ^-11) (3.35 × 10³⁰ )/( 6.09 × 10³ ) ²

= 6.024 x10 ¹² m/s ²

Initial speed u = 0

From the relation v ² - u ² = 2aS

v ² - 0 ² = 2gS Since accleration a = g

v = [2gS]

= [2x 6.024 x10 ¹² x0.013]

= 395.78 x10 ³ m/s

genius_generous answered 11 months ago

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