In: Physics
Our Sun, with mass 2.00×1030 kg, revolves about the center of the Milky Way galaxy, which is 2.20×1020 m away, once every 2.50×108 years. Assuming that each of the stars in the galaxy has a mass equal to that of our Sun, that the stars are distributed uniformly in a sphere about the galactic center, and that our Sun is essentially at the edge of that sphere, estimate roughly the number of stars in the galaxy.
If the mass of the sun is m, then the total mass of the stars in
the galaxy is Nm, where N is the number of stars. Assume the sun is
moving in a circle and use the formula for centripetal
acceleration. Then, the force of the galaxy on the sun is mv^2 / r
, where v is the sun's velocity around the center of the galaxy and
r is the galactic radius. From here, use Newton's law of gravity F
= G *m_1 * m_2 / r^2 (where the m's are the different masses, and r
again will be the galactic radius). Set the two forces equal to
each other. In this case, m_2 will be the mass of the galaxy
Nm.
F = GNm^2 / r^2 = mv^2 / r --->>> N = v^2 * r / (Gm)
The period of the orbit P = 2*pi*r / v, or, v = 2*pi*r / P.
Substituting this in to the previous expression,
N = 4*pi^2*r^3 / (G m P^2) [make sure to convert P into
seconds]
time period = P = 2.50×10^8 years = 2.50×10^8×12×30×24×60×60 seconds = 7.776×10^15 seconds
N = 4?^2×(2.20×10^20)/(6.67×10^-11×2×10^30×(7.776×10^15))
N = 5.21×10^10.....Approx.
Please check calculation carefuly.