Question

In: Computer Science

I want Algorithim of this c++ code #include<iostream> using namespace std; int main() { char repeat...

I want Algorithim of this c++ code

#include<iostream>

using namespace std;

int main()

{

char repeat = 'y';

for (;repeat == 'y';){

char emplyeename[35];

float basic_Salary,EPF, Dearness_Allow, tax, Net_Salary , emplyee_id;

cout << "Enter Basic Salary : ";

cin >> basic_Salary;

Dearness_Allow = 0.40 * basic_Salary;

switch (01)

{case 1:

if (basic_Salary <= 2,20,00)

EPF = 0;

case 2:

if (basic_Salary > 28000 && basic_Salary <= 60000)

EPF = 0.08*basic_Salary;

case 3:

if (basic_Salary > 60000 && basic_Salary <= 200000)

EPF = (0.17)*(basic_Salary - 60000) + 22300;

Net_Salary = basic_Salary + Dearness_Allow - EPF;

cout<<"Employee Id : ";

cin>>emplyee_id;

cout<<"Employee Name : ";

cin>>emplyeename;

cout<<"EPF : "<<EPF<<endl;

cout<<"Dearness Allow : "<<Dearness_Allow<<endl;

cout<<"Net Salary : "<<Net_Salary<<endl;

cout<<"Do you want to still continue....Yes/No "<<endl;

cin>>repeat;}}

return 0;}

Expert Solution

//Algorithm

1.Start

2. Assign repeat = 'y'

3. do the steps 3 .1 to 3.13 until (repeat equal to 'y')

3.1 input "Enter Basic Salary : ", basic_Salary

3.2 Dearness_Allow = 0.40 * basic_Salary

3.3 if (basic_Salary <= 2,20,00) then EPF = 0;

3.4 if (basic_Salary > 28000 and basic_Salary <= 60000) then EPF = 0.08*basic_Salary

3.5 if (basic_Salary > 60000 and basic_Salary <= 200000) then

EPF = (0.17)*(basic_Salary - 60000) + 22300

3.6 Net_Salary = basic_Salary + Dearness_Allow - EPF

3.7 Input "Employee Id : ",emplyee_id

3.8 Input "Employee Name : ",emplyeename

3.9 Display "EPF : ",EPF

3.10 Display "Dearness Allow : "Dearness_Allow

3.11 Display "Net Salary : ",Net_Salary

3.12 Display "Do you want to still continue....Yes/No "

3.13 Input repeat

4.Stop

Screen shot of the algorithm

Please comment if any query

venereology answered 1 year ago

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