In: Physics
Find the wavelength (in nm) of a photon whose energy is 9.00 × 10-19 J.
Given data
Energy(E)=9.00*10^(-19)
We know(E)=hf ( f=c/lamda)
So E=hc/lamda
Lamda =hc/E
=(6.63)*^10(-34)*(3)*10(^8)/(9.00)*10^(-19)
=(6.63)*(3)*(10)^(-26)(/9.00)*(10)^(-19)
=(19.89/9.00)*10(-7)
=2.21*10(-7) meters
=221 nm