How does one make a 2.50L solution that is 0.457M in potassium sulfate? Be specific as...

How does one make a 2.50L solution that is 0.457M in potassium sulfate? Be specific as to what is required for the preparation.

Expert Solution

no of moles of potassium sulfate (K2SO4) = molarity * volume in L

= 0.457*2.5

= 1.1425moles

mass of K2So4 = no of moles* gram molar mass

= 1.1425*174.259

= 199g

199g of K2So4 required to get 2.5L of 0.457M potassium sulfate

queen_honey_blossom answered 1 year ago

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