In: Operations Management
A mail-order house uses 15,950 boxes a year. Carrying costs are
69 cents per box a year, and ordering costs are $100. The following
price schedule applies.
Number of Boxes | Price per Box | ||
1,000 to 1,999 | $1.40 | ||
2,000 to 4,999 | 1.30 | ||
5,000 to 9,999 | 1.20 | ||
10,000 or more | 1.15 | ||
a. Determine the optimal order quantity. (Round
your answer to the nearest whole number.)
b. Determine the number of orders per year.
(Round your answer to 2 decimal places.)
Annual demand(D) = 15950 units
ordering cost(S) = $100
Holding cost(H) = 69 cents = $0.69
For this problem we have to first calculate the common Economic order Quantity as the holding cost for all range is the same.So the common EOQ = sqrt of (2DS/H)
= Sqrt of [(2X15950X100) / 0.69]
= 2150 units
We can order 2150 units at a price of $1.30
Total cost with order quantity(Q) of 2150 units = [(Q/2)/H] + [(D/Q)S] + (Price X D)
= [(2150/2)0.69] + [(15950/2150)100] + (1.30 X 15950)
= $741.75 + $741. 86 + $20735
= $22218.61
Because lower price ranges exist each must be checked against the cost generated by 2150 units at the price of $1.30
The minimum units required to order to obtain a price of $1.20 is 5000 units.So the total cost with an order quantity(Q) of 5000 units = [(Q/2)H] + [(D/Q)S] + (Price X D)
= [(5000/2)0.69] + [(15950/5000)100] + (1.20 X 15950)
= $1725 + $319 + $19140
= $21184
The minimum units required to order to obtain a price of $1.15 is 10000 units.So the total cost with an order quantity(Q) of 10000 units = [(Q/2)H] + [(D/Q)S] + (Price X D)
= [(10000/2)0.69] + [(15950/10000)100] + (1.15 X 15950)
= $3450 + $159. 5 + $18342.5
= $21952
So the optimal order quantity is 5000 boxes as it has the lowest total cost of $21184
b) Number of orders per year = D/Economic Order Quantity = 15950/5000 = 3.19