In: Chemistry
Calculate the Standard Reduction potential of Substance B when e = -0.62 V at 25 °C; [Breduced] = 50 µM, and [Boxidized] = 2 µM. Assume that n = 2.
Ecell = E0cell -RT/nF lnKeq
= E0cell -2.303RT/nF log[reduced form]/[oxidized form]
R = 8.314Joulemole-K
T 25+273 = 298K
F = 96500c
Ecell = E0cell - 2.303*8.314*298/n*96500 log[reduced form]/[oxidized form]
Ecell = E0cell - 0.0592/n log[reduced form]/[oxidized form]
n = 2
Ecell = -0.62v
[Breduced] = 50 µM, and [Boxidized] = 2 µM
-0.62 = E0cell - 0.0592/2 log50/2
-0.62 = E0cell -0.0296*1.3979
E0cell = -0.58v